7(v+4)=-2(8v-6)+9v

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Solution for 7(v+4)=-2(8v-6)+9v equation: 



7(v+4)=-2(8v-6)+9v

We move all terms to the left:

7(v+4)-(-2(8v-6)+9v)=0

We multiply parentheses

7v-(-2(8v-6)+9v)+28=0



We calculate terms in parentheses: -(-2(8v-6)+9v), so:

-2(8v-6)+9v

We add all the numbers together, and all the variables

9v-2(8v-6)

We multiply parentheses

9v-16v+12

We add all the numbers together, and all the variables

-7v+12

Back to the equation:

-(-7v+12)



We get rid of parentheses

7v+7v-12+28=0

We add all the numbers together, and all the variables

14v+16=0

We move all terms containing v to the left, all other terms to the right

14v=-16

v=-16/14

v=-1+1/7

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