4(8y+3)=6(7y+5)

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Solution for 4(8y+3)=6(7y+5) equation: 



4(8y+3)=6(7y+5)

We move all terms to the left:

4(8y+3)-(6(7y+5))=0

We multiply parentheses

32y-(6(7y+5))+12=0



We calculate terms in parentheses: -(6(7y+5)), so:

6(7y+5)

We multiply parentheses

42y+30

Back to the equation:

-(42y+30)



We get rid of parentheses

32y-42y-30+12=0

We add all the numbers together, and all the variables

-10y-18=0

We move all terms containing y to the left, all other terms to the right

-10y=18

y=18/-10

y=-1+4/5

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