7(v+2)=-4(4v-8)+9v

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Solution for 7(v+2)=-4(4v-8)+9v equation: 



7(v+2)=-4(4v-8)+9v

We move all terms to the left:

7(v+2)-(-4(4v-8)+9v)=0

We multiply parentheses

7v-(-4(4v-8)+9v)+14=0



We calculate terms in parentheses: -(-4(4v-8)+9v), so:

-4(4v-8)+9v

We add all the numbers together, and all the variables

9v-4(4v-8)

We multiply parentheses

9v-16v+32

We add all the numbers together, and all the variables

-7v+32

Back to the equation:

-(-7v+32)



We get rid of parentheses

7v+7v-32+14=0

We add all the numbers together, and all the variables

14v-18=0

We move all terms containing v to the left, all other terms to the right

14v=18

v=18/14

v=1+2/7

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