7(u-3)-1=-6(-4u+5)-5u

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Solution for 7(u-3)-1=-6(-4u+5)-5u equation: 



7(u-3)-1=-6(-4u+5)-5u

We move all terms to the left:

7(u-3)-1-(-6(-4u+5)-5u)=0

We multiply parentheses

7u-(-6(-4u+5)-5u)-21-1=0



We calculate terms in parentheses: -(-6(-4u+5)-5u), so:

-6(-4u+5)-5u

We add all the numbers together, and all the variables

-5u-6(-4u+5)

We multiply parentheses

-5u+24u-30

We add all the numbers together, and all the variables

19u-30

Back to the equation:

-(19u-30)



We add all the numbers together, and all the variables

7u-(19u-30)-22=0

We get rid of parentheses

7u-19u+30-22=0

We add all the numbers together, and all the variables

-12u+8=0

We move all terms containing u to the left, all other terms to the right

-12u=-8

u=-8/-12

u=2/3

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