3(7-d)-33=17d-4(3+5d)

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Solution for 3(7-d)-33=17d-4(3+5d) equation: 



3(7-d)-33=17d-4(3+5d)

We move all terms to the left:

3(7-d)-33-(17d-4(3+5d))=0

We add all the numbers together, and all the variables

3(-1d+7)-(17d-4(5d+3))-33=0

We multiply parentheses

-3d-(17d-4(5d+3))+21-33=0



We calculate terms in parentheses: -(17d-4(5d+3)), so:

17d-4(5d+3)

We multiply parentheses

17d-20d-12

We add all the numbers together, and all the variables

-3d-12

Back to the equation:

-(-3d-12)



We add all the numbers together, and all the variables

-3d-(-3d-12)-12=0

We get rid of parentheses

-3d+3d+12-12=0

We add all the numbers together, and all the variables

=0

d=0/1

d=0

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