7(u-1)=8u+2-3(-3u-2)

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Solution for 7(u-1)=8u+2-3(-3u-2) equation: 



7(u-1)=8u+2-3(-3u-2)

We move all terms to the left:

7(u-1)-(8u+2-3(-3u-2))=0

We multiply parentheses

7u-(8u+2-3(-3u-2))-7=0



We calculate terms in parentheses: -(8u+2-3(-3u-2)), so:

8u+2-3(-3u-2)

determiningTheFunctionDomain
8u-3(-3u-2)+2

We multiply parentheses

8u+9u+6+2

We add all the numbers together, and all the variables

17u+8

Back to the equation:

-(17u+8)



We get rid of parentheses

7u-17u-8-7=0

We add all the numbers together, and all the variables

-10u-15=0

We move all terms containing u to the left, all other terms to the right

-10u=15

u=15/-10

u=-1+1/2

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