If it's not what You are looking for type in the equation solver your own equation and let us solve it.
10c-45=3(c-15)
We move all terms to the left:
10c-45-(3(c-15))=0
We calculate terms in parentheses: -(3(c-15)), so:We get rid of parentheses
3(c-15)
We multiply parentheses
3c-45
Back to the equation:
-(3c-45)
10c-3c+45-45=0
We add all the numbers together, and all the variables
7c=0
c=0/7
c=0
| 8r²=3r+2=7r² | | h2-12h+36=0 | | r+3/9=4 | | 5x÷4=10 | | 12x–10=0 | | -20=-8x+6(x-4) | | 11x+23x=3 | | -5x+12=5x−5 | | 5x+2x-4+x=36 | | x+17=10;x= | | |x+8|=|7-x| | | 0y=23 | | 1/2v=2/3 | | 10x+12x+20=180 | | 4(2x+5)=-2(x-20) | | 11/2w=161/2 | | X+(50+x)=90 | | -(3-x)+5x=-4+27 | | 2(3x-18)=3x-6 | | 5=2r−1 | | 2(x–7)–10=12–4x | | X^2+6x-3=61 | | 2)-4(3x-1)=10-4x | | ⁵/²x+40=500 | | y/13=11/7 | | 1/3c+3/8c=3/4 | | 4(x=1)=2(6-2x) | | |7x+4|+5=7 | | 30=5(2x+8) | | 8a+42=58 | | 9+2x=x+6 | | 1x+2/5x=-5 |