7(s+1)=6(s-1)

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Solution for 7(s+1)=6(s-1) equation: 



7(s+1)=6(s-1)

We move all terms to the left:

7(s+1)-(6(s-1))=0

We multiply parentheses

7s-(6(s-1))+7=0



We calculate terms in parentheses: -(6(s-1)), so:

6(s-1)

We multiply parentheses

6s-6

Back to the equation:

-(6s-6)



We get rid of parentheses

7s-6s+6+7=0

We add all the numbers together, and all the variables

s+13=0

We move all terms containing s to the left, all other terms to the right

s=-13

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