2(u-1)=6u+4-2(-3u-6)

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Solution for 2(u-1)=6u+4-2(-3u-6) equation: 



2(u-1)=6u+4-2(-3u-6)

We move all terms to the left:

2(u-1)-(6u+4-2(-3u-6))=0

We multiply parentheses

2u-(6u+4-2(-3u-6))-2=0



We calculate terms in parentheses: -(6u+4-2(-3u-6)), so:

6u+4-2(-3u-6)

determiningTheFunctionDomain
6u-2(-3u-6)+4

We multiply parentheses

6u+6u+12+4

We add all the numbers together, and all the variables

12u+16

Back to the equation:

-(12u+16)



We get rid of parentheses

2u-12u-16-2=0

We add all the numbers together, and all the variables

-10u-18=0

We move all terms containing u to the left, all other terms to the right

-10u=18

u=18/-10

u=-1+4/5

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