9+5(2y-1)=-4(3y-2)+6y

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Solution for 9+5(2y-1)=-4(3y-2)+6y equation: 



9+5(2y-1)=-4(3y-2)+6y

We move all terms to the left:

9+5(2y-1)-(-4(3y-2)+6y)=0

We multiply parentheses

10y-(-4(3y-2)+6y)-5+9=0



We calculate terms in parentheses: -(-4(3y-2)+6y), so:

-4(3y-2)+6y

We add all the numbers together, and all the variables

6y-4(3y-2)

We multiply parentheses

6y-12y+8

We add all the numbers together, and all the variables

-6y+8

Back to the equation:

-(-6y+8)



We add all the numbers together, and all the variables

10y-(-6y+8)+4=0

We get rid of parentheses

10y+6y-8+4=0

We add all the numbers together, and all the variables

16y-4=0

We move all terms containing y to the left, all other terms to the right

16y=4

y=4/16

y=1/4

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