7(r-3)-6(r-1)=2(r+7)

Solution for 7(r-3)-6(r-1)=2(r+7) equation:

7(r-3)-6(r-1)=2(r+7)

We move all terms to the left:

7(r-3)-6(r-1)-(2(r+7))=0

We multiply parentheses

7r-6r-(2(r+7))-21+6=0


We calculate terms in parentheses: -(2(r+7)), so:

2(r+7)

We multiply parentheses

2r+14

Back to the equation:

-(2r+14)


We add all the numbers together, and all the variables

r-(2r+14)-15=0

We get rid of parentheses

r-2r-14-15=0

We add all the numbers together, and all the variables

-1r-29=0

We move all terms containing r to the left, all other terms to the right

-r=29

r=29/-1

r=-29