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3x+2x(x-5)=50
We move all terms to the left:
3x+2x(x-5)-(50)=0
We multiply parentheses
2x^2+3x-10x-50=0
We add all the numbers together, and all the variables
2x^2-7x-50=0
a = 2; b = -7; c = -50;
Δ = b2-4ac
Δ = -72-4·2·(-50)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{449}}{2*2}=\frac{7-\sqrt{449}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{449}}{2*2}=\frac{7+\sqrt{449}}{4} $
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