3(2y+2)-y=2(y-3)

Solution for 3(2y+2)-y=2(y-3) equation:

3(2y+2)-y=2(y-3)

We move all terms to the left:

3(2y+2)-y-(2(y-3))=0

We add all the numbers together, and all the variables

-1y+3(2y+2)-(2(y-3))=0

We multiply parentheses

-1y+6y-(2(y-3))+6=0


We calculate terms in parentheses: -(2(y-3)), so:

2(y-3)

We multiply parentheses

2y-6

Back to the equation:

-(2y-6)


We add all the numbers together, and all the variables

5y-(2y-6)+6=0

We get rid of parentheses

5y-2y+6+6=0

We add all the numbers together, and all the variables

3y+12=0

We move all terms containing y to the left, all other terms to the right

3y=-12

y=-12/3

y=-4