7(r-10)=3(r+24)

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Solution for 7(r-10)=3(r+24) equation:



7(r-10)=3(r+24)
We move all terms to the left:
7(r-10)-(3(r+24))=0
We multiply parentheses
7r-(3(r+24))-70=0
We calculate terms in parentheses: -(3(r+24)), so:
3(r+24)
We multiply parentheses
3r+72
Back to the equation:
-(3r+72)
We get rid of parentheses
7r-3r-72-70=0
We add all the numbers together, and all the variables
4r-142=0
We move all terms containing r to the left, all other terms to the right
4r=142
r=142/4
r=35+1/2

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