-24=2(b-3)+8

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Solution for -24=2(b-3)+8 equation: 



-24=2(b-3)+8

We move all terms to the left:

-24-(2(b-3)+8)=0



We calculate terms in parentheses: -(2(b-3)+8), so:

2(b-3)+8

We multiply parentheses

2b-6+8

We add all the numbers together, and all the variables

2b+2

Back to the equation:

-(2b+2)



We get rid of parentheses

-2b-2-24=0

We add all the numbers together, and all the variables

-2b-26=0

We move all terms containing b to the left, all other terms to the right

-2b=26

b=26/-2

b=-13

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