7(q+3)=107-q

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Solution for 7(q+3)=107-q equation: 



7(q+3)=107-q

We move all terms to the left:

7(q+3)-(107-q)=0

We add all the numbers together, and all the variables

7(q+3)-(-1q+107)=0

We multiply parentheses

7q-(-1q+107)+21=0

We get rid of parentheses

7q+1q-107+21=0

We add all the numbers together, and all the variables

8q-86=0

We move all terms containing q to the left, all other terms to the right

8q=86

q=86/8

q=10+3/4

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