7(p-2)-3=3(p+1)+8

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Solution for 7(p-2)-3=3(p+1)+8 equation: 



7(p-2)-3=3(p+1)+8

We move all terms to the left:

7(p-2)-3-(3(p+1)+8)=0

We multiply parentheses

7p-(3(p+1)+8)-14-3=0



We calculate terms in parentheses: -(3(p+1)+8), so:

3(p+1)+8

We multiply parentheses

3p+3+8

We add all the numbers together, and all the variables

3p+11

Back to the equation:

-(3p+11)



We add all the numbers together, and all the variables

7p-(3p+11)-17=0

We get rid of parentheses

7p-3p-11-17=0

We add all the numbers together, and all the variables

4p-28=0

We move all terms containing p to the left, all other terms to the right

4p=28

p=28/4

p=7

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