3(2h-5)-2=2(h+2)+7

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Solution for 3(2h-5)-2=2(h+2)+7 equation: 



3(2h-5)-2=2(h+2)+7

We move all terms to the left:

3(2h-5)-2-(2(h+2)+7)=0

We multiply parentheses

6h-(2(h+2)+7)-15-2=0



We calculate terms in parentheses: -(2(h+2)+7), so:

2(h+2)+7

We multiply parentheses

2h+4+7

We add all the numbers together, and all the variables

2h+11

Back to the equation:

-(2h+11)



We add all the numbers together, and all the variables

6h-(2h+11)-17=0

We get rid of parentheses

6h-2h-11-17=0

We add all the numbers together, and all the variables

4h-28=0

We move all terms containing h to the left, all other terms to the right

4h=28

h=28/4

h=7

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