7(n-4)-2n=4(n-3)

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Solution for 7(n-4)-2n=4(n-3) equation: 



7(n-4)-2n=4(n-3)

We move all terms to the left:

7(n-4)-2n-(4(n-3))=0

We add all the numbers together, and all the variables

-2n+7(n-4)-(4(n-3))=0

We multiply parentheses

-2n+7n-(4(n-3))-28=0



We calculate terms in parentheses: -(4(n-3)), so:

4(n-3)

We multiply parentheses

4n-12

Back to the equation:

-(4n-12)



We add all the numbers together, and all the variables

5n-(4n-12)-28=0

We get rid of parentheses

5n-4n+12-28=0

We add all the numbers together, and all the variables

n-16=0

We move all terms containing n to the left, all other terms to the right

n=16

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