8(4x-7)=64x

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Solution for 8(4x-7)=64x equation: 



8(4x-7)=64x

We move all terms to the left:

8(4x-7)-(64x)=0

We add all the numbers together, and all the variables

-64x+8(4x-7)=0

We multiply parentheses

-64x+32x-56=0

We add all the numbers together, and all the variables

-32x-56=0

We move all terms containing x to the left, all other terms to the right

-32x=56

x=56/-32

x=-1+3/4

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