7(n-3)=2(n-9)+2n

Solution for 7(n-3)=2(n-9)+2n equation:

7(n-3)=2(n-9)+2n

We move all terms to the left:

7(n-3)-(2(n-9)+2n)=0

We multiply parentheses

7n-(2(n-9)+2n)-21=0


We calculate terms in parentheses: -(2(n-9)+2n), so:

2(n-9)+2n

We add all the numbers together, and all the variables

2n+2(n-9)

We multiply parentheses

2n+2n-18

We add all the numbers together, and all the variables

4n-18

Back to the equation:

-(4n-18)


We get rid of parentheses

7n-4n+18-21=0

We add all the numbers together, and all the variables

3n-3=0

We move all terms containing n to the left, all other terms to the right

3n=3

n=3/3

n=1