-(c+12)+8(c+1)=10

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Solution for -(c+12)+8(c+1)=10 equation: 



-(c+12)+8(c+1)=10

We move all terms to the left:

-(c+12)+8(c+1)-(10)=0

We multiply parentheses

-(c+12)+8c+8-10=0

We get rid of parentheses

-c+8c-12+8-10=0

We add all the numbers together, and all the variables

7c-14=0

We move all terms containing c to the left, all other terms to the right

7c=14

c=14/7

c=2

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