7(m-6)=-32+2m

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Solution for 7(m-6)=-32+2m equation:



7(m-6)=-32+2m
We move all terms to the left:
7(m-6)-(-32+2m)=0
We add all the numbers together, and all the variables
7(m-6)-(2m-32)=0
We multiply parentheses
7m-(2m-32)-42=0
We get rid of parentheses
7m-2m+32-42=0
We add all the numbers together, and all the variables
5m-10=0
We move all terms containing m to the left, all other terms to the right
5m=10
m=10/5
m=2

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