3x-7(2-x)=(x-4)+3x+20

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Solution for 3x-7(2-x)=(x-4)+3x+20 equation: 



3x-7(2-x)=(x-4)+3x+20

We move all terms to the left:

3x-7(2-x)-((x-4)+3x+20)=0

We add all the numbers together, and all the variables

3x-7(-1x+2)-((x-4)+3x+20)=0

We multiply parentheses

3x+7x-((x-4)+3x+20)-14=0



We calculate terms in parentheses: -((x-4)+3x+20), so:

(x-4)+3x+20

We add all the numbers together, and all the variables

3x+(x-4)+20

We get rid of parentheses

3x+x-4+20

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We add all the numbers together, and all the variables

10x-(4x+16)-14=0

We get rid of parentheses

10x-4x-16-14=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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