7(m+2)+8=-6(m-9)-3m

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Solution for 7(m+2)+8=-6(m-9)-3m equation: 



7(m+2)+8=-6(m-9)-3m

We move all terms to the left:

7(m+2)+8-(-6(m-9)-3m)=0

We multiply parentheses

7m-(-6(m-9)-3m)+14+8=0



We calculate terms in parentheses: -(-6(m-9)-3m), so:

-6(m-9)-3m

We add all the numbers together, and all the variables

-3m-6(m-9)

We multiply parentheses

-3m-6m+54

We add all the numbers together, and all the variables

-9m+54

Back to the equation:

-(-9m+54)



We add all the numbers together, and all the variables

7m-(-9m+54)+22=0

We get rid of parentheses

7m+9m-54+22=0

We add all the numbers together, and all the variables

16m-32=0

We move all terms containing m to the left, all other terms to the right

16m=32

m=32/16

m=2

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