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2/5h-7=2/5-2h+3
We move all terms to the left:
2/5h-7-(2/5-2h+3)=0
Domain of the equation: 5h!=0
h!=0/5
h!=0
h∈R
Domain of the equation: 5-2h+3)!=0We add all the numbers together, and all the variables
We move all terms containing h to the left, all other terms to the right
-2h+3)!=-5
h∈R
2/5h-(-2h+2/5+3)-7=0
We get rid of parentheses
2/5h+2h-3-7-2/5=0
We calculate fractions
2h-3-7=0
We add all the numbers together, and all the variables
2h-10=0
We move all terms containing h to the left, all other terms to the right
2h=10
h=10/2
h=5
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