7(k-3)=3k-4

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Solution for 7(k-3)=3k-4 equation: 



7(k-3)=3k-4

We move all terms to the left:

7(k-3)-(3k-4)=0

We multiply parentheses

7k-(3k-4)-21=0

We get rid of parentheses

7k-3k+4-21=0

We add all the numbers together, and all the variables

4k-17=0

We move all terms containing k to the left, all other terms to the right

4k=17

k=17/4

k=4+1/4

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