25-(2c+4)=2(c+3)=c

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Solution for 25-(2c+4)=2(c+3)=c equation: 



25-(2c+4)=2(c+3)=c

We move all terms to the left:

25-(2c+4)-(2(c+3))=0

We get rid of parentheses

-2c-(2(c+3))-4+25=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We add all the numbers together, and all the variables

-2c-(2c+6)+21=0

We get rid of parentheses

-2c-2c-6+21=0

We add all the numbers together, and all the variables

-4c+15=0

We move all terms containing c to the left, all other terms to the right

-4c=-15

c=-15/-4

c=3+3/4

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