7(k-3)=3(k-5)

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Solution for 7(k-3)=3(k-5) equation: 



7(k-3)=3(k-5)

We move all terms to the left:

7(k-3)-(3(k-5))=0

We multiply parentheses

7k-(3(k-5))-21=0



We calculate terms in parentheses: -(3(k-5)), so:

3(k-5)

We multiply parentheses

3k-15

Back to the equation:

-(3k-15)



We get rid of parentheses

7k-3k+15-21=0

We add all the numbers together, and all the variables

4k-6=0

We move all terms containing k to the left, all other terms to the right

4k=6

k=6/4

k=1+1/2

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