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x+1(4/5+3)=2/3x-4
We move all terms to the left:
x+1(4/5+3)-(2/3x-4)=0
Domain of the equation: 3x-4)!=0We get rid of parentheses
x∈R
x-2/3x+4+1(4/5+3)=0
We calculate fractions
x+()/15x+(1(4*3x)/15x+4=0
We add all the numbers together, and all the variables
x+()/15x+(1(+4*3x)/15x+4=0
We calculate fractions
x+(()*15x+4)/(225x^2+4)+((1(+4*3x)*15x)/(225x^2+4)=0
We calculate terms in parentheses: +(()*15x+4)/(225x^2+4), so:
()*15x+4)/(225x^2+4
We multiply all the terms by the denominator
(()*15x)*(225x^2+4)+4*(225x^2
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
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We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
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()*15x)*(225x^2+4
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()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
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()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
()*15x)*(225x^2+4
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()*15x)*(225x^2+4
We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
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()*15x)*(225x^2+4
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()*15x)*(225x^2+4
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We calculate terms in parentheses: +(()*15x)*(225x^2+4), so:
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We calcu
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