7(c+2)=6c-1

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Solution for 7(c+2)=6c-1 equation: 



7(c+2)=6c-1

We move all terms to the left:

7(c+2)-(6c-1)=0

We multiply parentheses

7c-(6c-1)+14=0

We get rid of parentheses

7c-6c+1+14=0

We add all the numbers together, and all the variables

c+15=0

We move all terms containing c to the left, all other terms to the right

c=-15

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