(k+5)/10=(k-12)/9

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Solution for (k+5)/10=(k-12)/9 equation: 



(k+5)/10=(k-12)/9

We move all terms to the left:

(k+5)/10-((k-12)/9)=0

We calculate fractions


k/()+(-((k-12)*10)/()=0



We calculate terms in parentheses: +(-((k-12)*10)/(), so:

-((k-12)*10)/(

We multiply all the terms by the denominator


-((k-12)*10)



We calculate terms in parentheses: -((k-12)*10), so:

(k-12)*10

We multiply parentheses

10k-120

Back to the equation:

-(10k-120)



We get rid of parentheses

-10k+120

Back to the equation:

+(-10k+120)



We get rid of parentheses

k/()-10k+120=0

We multiply all the terms by the denominator


k-10k*()+120*()=0

We add all the numbers together, and all the variables

k-10k*()=0

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