7(b-8)=9(b+2)

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Solution for 7(b-8)=9(b+2) equation: 



7(b-8)=9(b+2)

We move all terms to the left:

7(b-8)-(9(b+2))=0

We multiply parentheses

7b-(9(b+2))-56=0



We calculate terms in parentheses: -(9(b+2)), so:

9(b+2)

We multiply parentheses

9b+18

Back to the equation:

-(9b+18)



We get rid of parentheses

7b-9b-18-56=0

We add all the numbers together, and all the variables

-2b-74=0

We move all terms containing b to the left, all other terms to the right

-2b=74

b=74/-2

b=-37

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