2(6-x)+15=72+3(x-2)

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Solution for 2(6-x)+15=72+3(x-2) equation: 



2(6-x)+15=72+3(x-2)

We move all terms to the left:

2(6-x)+15-(72+3(x-2))=0

We add all the numbers together, and all the variables

2(-1x+6)-(72+3(x-2))+15=0

We multiply parentheses

-2x-(72+3(x-2))+12+15=0



We calculate terms in parentheses: -(72+3(x-2)), so:

72+3(x-2)

determiningTheFunctionDomain
3(x-2)+72

We multiply parentheses

3x-6+72

We add all the numbers together, and all the variables

3x+66

Back to the equation:

-(3x+66)



We add all the numbers together, and all the variables

-2x-(3x+66)+27=0

We get rid of parentheses

-2x-3x-66+27=0

We add all the numbers together, and all the variables

-5x-39=0

We move all terms containing x to the left, all other terms to the right

-5x=39

x=39/-5

x=-7+4/5

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