7(b-8)-4=8(b-2)+3b

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Solution for 7(b-8)-4=8(b-2)+3b equation: 



7(b-8)-4=8(b-2)+3b

We move all terms to the left:

7(b-8)-4-(8(b-2)+3b)=0

We multiply parentheses

7b-(8(b-2)+3b)-56-4=0



We calculate terms in parentheses: -(8(b-2)+3b), so:

8(b-2)+3b

We add all the numbers together, and all the variables

3b+8(b-2)

We multiply parentheses

3b+8b-16

We add all the numbers together, and all the variables

11b-16

Back to the equation:

-(11b-16)



We add all the numbers together, and all the variables

7b-(11b-16)-60=0

We get rid of parentheses

7b-11b+16-60=0

We add all the numbers together, and all the variables

-4b-44=0

We move all terms containing b to the left, all other terms to the right

-4b=44

b=44/-4

b=-11

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