3(t+2)=5(t-4)

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Solution for 3(t+2)=5(t-4) equation: 



3(t+2)=5(t-4)

We move all terms to the left:

3(t+2)-(5(t-4))=0

We multiply parentheses

3t-(5(t-4))+6=0



We calculate terms in parentheses: -(5(t-4)), so:

5(t-4)

We multiply parentheses

5t-20

Back to the equation:

-(5t-20)



We get rid of parentheses

3t-5t+20+6=0

We add all the numbers together, and all the variables

-2t+26=0

We move all terms containing t to the left, all other terms to the right

-2t=-26

t=-26/-2

t=+13

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