(x-3)/8=(x-4)/7

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Solution for (x-3)/8=(x-4)/7 equation: 



(x-3)/8=(x-4)/7

We move all terms to the left:

(x-3)/8-((x-4)/7)=0

We calculate fractions


x/()+(-((x-4)*8)/()=0



We calculate terms in parentheses: +(-((x-4)*8)/(), so:

-((x-4)*8)/(

We multiply all the terms by the denominator


-((x-4)*8)



We calculate terms in parentheses: -((x-4)*8), so:

(x-4)*8

We multiply parentheses

8x-32

Back to the equation:

-(8x-32)



We get rid of parentheses

-8x+32

Back to the equation:

+(-8x+32)



We get rid of parentheses

x/()-8x+32=0

We multiply all the terms by the denominator


x-8x*()+32*()=0

We add all the numbers together, and all the variables

x-8x*()=0

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