7(a-4)-2a=19+3(a+2)

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Solution for 7(a-4)-2a=19+3(a+2) equation: 



7(a-4)-2a=19+3(a+2)

We move all terms to the left:

7(a-4)-2a-(19+3(a+2))=0

We add all the numbers together, and all the variables

-2a+7(a-4)-(19+3(a+2))=0

We multiply parentheses

-2a+7a-(19+3(a+2))-28=0



We calculate terms in parentheses: -(19+3(a+2)), so:

19+3(a+2)

determiningTheFunctionDomain
3(a+2)+19

We multiply parentheses

3a+6+19

We add all the numbers together, and all the variables

3a+25

Back to the equation:

-(3a+25)



We add all the numbers together, and all the variables

5a-(3a+25)-28=0

We get rid of parentheses

5a-3a-25-28=0

We add all the numbers together, and all the variables

2a-53=0

We move all terms containing a to the left, all other terms to the right

2a=53

a=53/2

a=26+1/2

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