-28+2r=2(2+3r)

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Solution for -28+2r=2(2+3r) equation: 



-28+2r=2(2+3r)

We move all terms to the left:

-28+2r-(2(2+3r))=0

We add all the numbers together, and all the variables

2r-(2(3r+2))-28=0



We calculate terms in parentheses: -(2(3r+2)), so:

2(3r+2)

We multiply parentheses

6r+4

Back to the equation:

-(6r+4)



We get rid of parentheses

2r-6r-4-28=0

We add all the numbers together, and all the variables

-4r-32=0

We move all terms containing r to the left, all other terms to the right

-4r=32

r=32/-4

r=-8

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