20+4z=32

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Solution for 20+4z=32 equation: 



20+4z=32

We move all terms to the left:

20+4z-(32)=0

We add all the numbers together, and all the variables

4z-12=0

We move all terms containing z to the left, all other terms to the right

4z=12

z=12/4

z=3

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