7(a-4)+5=3(a+5)+6

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Solution for 7(a-4)+5=3(a+5)+6 equation: 



7(a-4)+5=3(a+5)+6

We move all terms to the left:

7(a-4)+5-(3(a+5)+6)=0

We multiply parentheses

7a-(3(a+5)+6)-28+5=0



We calculate terms in parentheses: -(3(a+5)+6), so:

3(a+5)+6

We multiply parentheses

3a+15+6

We add all the numbers together, and all the variables

3a+21

Back to the equation:

-(3a+21)



We add all the numbers together, and all the variables

7a-(3a+21)-23=0

We get rid of parentheses

7a-3a-21-23=0

We add all the numbers together, and all the variables

4a-44=0

We move all terms containing a to the left, all other terms to the right

4a=44

a=44/4

a=11

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