7(9x-3)-2=8(9-4x)+3x

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Solution for 7(9x-3)-2=8(9-4x)+3x equation: 



7(9x-3)-2=8(9-4x)+3x

We move all terms to the left:

7(9x-3)-2-(8(9-4x)+3x)=0

We add all the numbers together, and all the variables

7(9x-3)-(8(-4x+9)+3x)-2=0

We multiply parentheses

63x-(8(-4x+9)+3x)-21-2=0



We calculate terms in parentheses: -(8(-4x+9)+3x), so:

8(-4x+9)+3x

We add all the numbers together, and all the variables

3x+8(-4x+9)

We multiply parentheses

3x-32x+72

We add all the numbers together, and all the variables

-29x+72

Back to the equation:

-(-29x+72)



We add all the numbers together, and all the variables

63x-(-29x+72)-23=0

We get rid of parentheses

63x+29x-72-23=0

We add all the numbers together, and all the variables

92x-95=0

We move all terms containing x to the left, all other terms to the right

92x=95

x=95/92

x=1+3/92

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