7(7+2l)=3(9l+1)

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Solution for 7(7+2l)=3(9l+1) equation: 



7(7+2l)=3(9l+1)

We move all terms to the left:

7(7+2l)-(3(9l+1))=0

We add all the numbers together, and all the variables

7(2l+7)-(3(9l+1))=0

We multiply parentheses

14l-(3(9l+1))+49=0



We calculate terms in parentheses: -(3(9l+1)), so:

3(9l+1)

We multiply parentheses

27l+3

Back to the equation:

-(27l+3)



We get rid of parentheses

14l-27l-3+49=0

We add all the numbers together, and all the variables

-13l+46=0

We move all terms containing l to the left, all other terms to the right

-13l=-46

l=-46/-13

l=3+7/13

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