(2/3)y=5/12

Solution for (2/3)y=5/12 equation:

(2/3)y=5/12

We move all terms to the left:

(2/3)y-(5/12)=0


Domain of the equation: 3)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+2/3)y-(+5/12)=0

We multiply parentheses

2y^2-(+5/12)=0

We get rid of parentheses

2y^2-5/12=0

We multiply all the terms by the denominator


2y^2*12-5=0

Wy multiply elements

24y^2-5=0

a = 24; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·24·(-5)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{30}}{2*24}=\frac{0-4\sqrt{30}}{48}
=-\frac{4\sqrt{30}}{48}
=-\frac{\sqrt{30}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{30}}{2*24}=\frac{0+4\sqrt{30}}{48}
=\frac{4\sqrt{30}}{48}
=\frac{\sqrt{30}}{12}
$