7(6-2y)=5-(3y+1)

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Solution for 7(6-2y)=5-(3y+1) equation: 



7(6-2y)=5-(3y+1)

We move all terms to the left:

7(6-2y)-(5-(3y+1))=0

We add all the numbers together, and all the variables

7(-2y+6)-(5-(3y+1))=0

We multiply parentheses

-14y-(5-(3y+1))+42=0



We calculate terms in parentheses: -(5-(3y+1)), so:

5-(3y+1)

determiningTheFunctionDomain
-(3y+1)+5

We get rid of parentheses

-3y-1+5

We add all the numbers together, and all the variables

-3y+4

Back to the equation:

-(-3y+4)



We get rid of parentheses

-14y+3y-4+42=0

We add all the numbers together, and all the variables

-11y+38=0

We move all terms containing y to the left, all other terms to the right

-11y=-38

y=-38/-11

y=3+5/11

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