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3(x+2)-6=6x-2(1+x)
We move all terms to the left:
3(x+2)-6-(6x-2(1+x))=0
We add all the numbers together, and all the variables
3(x+2)-(6x-2(x+1))-6=0
We multiply parentheses
3x-(6x-2(x+1))+6-6=0
We calculate terms in parentheses: -(6x-2(x+1)), so:We add all the numbers together, and all the variables
6x-2(x+1)
We multiply parentheses
6x-2x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
3x-(4x-2)=0
We get rid of parentheses
3x-4x+2=0
We add all the numbers together, and all the variables
-1x+2=0
We move all terms containing x to the left, all other terms to the right
-x=-2
x=-2/-1
x=+2
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