7(5y-6)=+3(2y+4)

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Solution for 7(5y-6)=+3(2y+4) equation: 



7(5y-6)=+3(2y+4)

We move all terms to the left:

7(5y-6)-(+3(2y+4))=0

We multiply parentheses

35y-(+3(2y+4))-42=0



We calculate terms in parentheses: -(+3(2y+4)), so:

+3(2y+4)

determiningTheFunctionDomain
3(2y+4)

We multiply parentheses

6y+12

Back to the equation:

-(6y+12)



We get rid of parentheses

35y-6y-12-42=0

We add all the numbers together, and all the variables

29y-54=0

We move all terms containing y to the left, all other terms to the right

29y=54

y=54/29

y=1+25/29

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