12=2(k-3)+8k

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Solution for 12=2(k-3)+8k equation: 



12=2(k-3)+8k

We move all terms to the left:

12-(2(k-3)+8k)=0



We calculate terms in parentheses: -(2(k-3)+8k), so:

2(k-3)+8k

We add all the numbers together, and all the variables

8k+2(k-3)

We multiply parentheses

8k+2k-6

We add all the numbers together, and all the variables

10k-6

Back to the equation:

-(10k-6)



We get rid of parentheses

-10k+6+12=0

We add all the numbers together, and all the variables

-10k+18=0

We move all terms containing k to the left, all other terms to the right

-10k=-18

k=-18/-10

k=1+4/5

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