7(5y-2)+6(2y+6)=25(3y+2)-16y

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Solution for 7(5y-2)+6(2y+6)=25(3y+2)-16y equation: 



7(5y-2)+6(2y+6)=25(3y+2)-16y

We move all terms to the left:

7(5y-2)+6(2y+6)-(25(3y+2)-16y)=0

We multiply parentheses

35y+12y-(25(3y+2)-16y)-14+36=0



We calculate terms in parentheses: -(25(3y+2)-16y), so:

25(3y+2)-16y

We add all the numbers together, and all the variables

-16y+25(3y+2)

We multiply parentheses

-16y+75y+50

We add all the numbers together, and all the variables

59y+50

Back to the equation:

-(59y+50)



We add all the numbers together, and all the variables

47y-(59y+50)+22=0

We get rid of parentheses

47y-59y-50+22=0

We add all the numbers together, and all the variables

-12y-28=0

We move all terms containing y to the left, all other terms to the right

-12y=28

y=28/-12

y=-2+1/3

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