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5(-2+x)=3(4+x)
We move all terms to the left:
5(-2+x)-(3(4+x))=0
We add all the numbers together, and all the variables
5(x-2)-(3(x+4))=0
We multiply parentheses
5x-(3(x+4))-10=0
We calculate terms in parentheses: -(3(x+4)), so:We get rid of parentheses
3(x+4)
We multiply parentheses
3x+12
Back to the equation:
-(3x+12)
5x-3x-12-10=0
We add all the numbers together, and all the variables
2x-22=0
We move all terms containing x to the left, all other terms to the right
2x=22
x=22/2
x=11
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